Maximum permutations???

by **Halmir** on Sat Jan 03, 2009 3:55 pm

So we've got over 100 maps x 2 -8 players x standard/terminator/assassin/doubles/triples/quads x escalating/fixed spoils/no spoils x etc etc.

Has anyone worked out how many possible variants of games there are now that can be set up? must be in the hundreds of thousands...!

by **The Neon Peon** on Sat Jan 03, 2009 4:03 pm

203,112 is all maps (counting the fact that AoR maps and Feudal have limits on player) on all numbers of players, all modes of gameplay, all card amounts, all reinforcement rules, fog, and speed.

by **BaldAdonis** on Sat Jan 03, 2009 4:04 pm

The Neon Peon wrote:203,112 is all maps (counting the fact that AoR maps and Feudal have limits on player) on all numbers of players, all modes of gameplay, all card amounts, all reinforcement rules, fog, and speed.

Are you sure?

by **e_i_pi** on Sat Jan 03, 2009 4:06 pm

BaldAdonis wrote:
The Neon Peon wrote:203,112 is all maps (counting the fact that AoR maps and Feudal have limits on player) on all numbers of players, all modes of gameplay, all card amounts, all reinforcement rules, fog, and speed.

Are you sure?

Yeah, but only about 12 of those settings are worth playing

by **Jeff Hardy** on Sat Jan 03, 2009 4:06 pm

isnt it more than that?

by **The Neon Peon** on Sat Jan 03, 2009 4:08 pm

Jeff Hardy wrote:isnt it more than that?

Nope, not when I did it.

by **BaldAdonis** on Sat Jan 03, 2009 4:09 pm

It's less.

show

by **The Neon Peon** on Sat Jan 03, 2009 4:10 pm

I know, I accounted in team games and maps with less players.

[ 7 x 3 (singleplayer) + 3 (doubles) + 2 (trips and quads) ] x 2 (play order) x 3 (cards) x 3 (forts) x 2 (fog) x 2 (speed) = 1872 for any normal map X 111 (assuming all maps are normal = 207,792 (But I did the calculation accounting for the odd maps.

by **Robinette** on Sat Jan 03, 2009 6:21 pm

This was from a prior thread... not long ago... based on 111 maps (which is still current)

Robinette wrote:
Natewolfman wrote:to play every map on every possible combination of games/settings, you will have to play 191,808 games

Well whatta ya know... I get the same number... 191,808

I really thought it would be 207,792...
but turns out you can't play 2 player terminator or 2 player assassin.......................

this is based on the 111 maps (at this moment),
and each additional map will add 1,728 games (with the settings available at this moment)

Feel free to double check these numbers... i did this on the fly...

But it was pointed out that the correct answer is a few less,
something to do with odd games like AoR with less Options :-s

by **The Neon Peon** on Sat Jan 03, 2009 6:25 pm

Ooops. No 2 player terminator or assassin. Let me recalculate.

by **The Neon Peon** on Sat Jan 03, 2009 6:35 pm

Correct Calculation:

[ 7 (standard) + 6 x 2 (terms and assassins) + 3 (doubles) + 2 (trips and quads) ] x 2 (play order) x 3 (cards) x 3 (forts) x 2 (fog) x 2 (speed) = 1728 for any normal map X 107 = 184,896

AoRs I, II, Fedual: [ 5 (standard) + 4 x 2 (terms and assassins) + 2 (doubles) + 1 (trips) ] x 2 (play order) x 3 (cards) x 3 (forts) x 2 (fog) x 2 (speed) = 1152 for the maps X 3 = 3456

AoR 3: [ 6 (standard) + 5 x 2 (terms and assassins) + 2 (doubles) + 1 (trips) ] x 2 (play order) x 3 (cards) x 3 (forts) x 2 (fog) x 2 (speed) = 1368

184,896 + 3456 + 1368 = 189,720

by **Timminz** on Sat Jan 03, 2009 6:46 pm

The Neon Peon wrote:I agree completely with BaldAdonis

by **The Neon Peon** on Sat Jan 03, 2009 6:49 pm

Timminz wrote:
The Neon Peon wrote:I agree completely with BaldAdonis

I did not even notice. Good catch. =D>

by **Robinette** on Sat Jan 03, 2009 6:57 pm

The Neon Peon wrote:Correct Calculation:

[ 7 (standard) + 6 x 2 (terms and assassins) + 3 (doubles) + 2 (trips and quads) ] x 2 (play order) x 3 (cards) x 3 (forts) x 2 (fog) x 2 (speed) = 1728 for any normal map X 107 = 184,896

AoRs I, II, Fedual: [ 5 (standard) + 4 x 2 (terms and assassins) + 2 (doubles) + 1 (trips) ] x 2 (play order) x 3 (cards) x 3 (forts) x 2 (fog) x 2 (speed) = 1152 for the maps X 3 = 3456

AoR 3: [ 6 (standard) + 5 x 2 (terms and assassins) + 2 (doubles) + 1 (trips) ] x 2 (play order) x 3 (cards) x 3 (forts) x 2 (fog) x 2 (speed) = 1368

184,896 + 3456 + 1368 = 189,720

well i don't know what all those formulas mean...

but using my abacus, i get exactly the same number... 189,720

And every new 'normal' map will add 1,728...
So we need 6 more maps to break 200,000

by **sully800** on Sun Jan 04, 2009 12:10 pm

Or one new option and then the possibilities go through the roof!

by **lancehoch** on Sun Jan 04, 2009 4:00 pm

sully800 wrote:Or one new option and then the possibilities go through the roof!

You mean an option like infected neutrals which will double the whole thing?

by **The Neon Peon** on Sun Jan 04, 2009 4:00 pm

lancehoch wrote:
sully800 wrote:Or one new option and then the possibilities go through the roof!

You mean an option like infected neutrals which will double the whole thing?

Yep.

by **Gypsys Kiss** on Sun Jan 04, 2009 4:57 pm

Are you differentiating between 4, 6 and 8 player doubles, or counting them as the same?

by **The Neon Peon** on Sun Jan 04, 2009 4:58 pm

Gypsys Kiss wrote:Are you differentiating between 4, 6 and 8 player doubles, or counting them as the same?

Different, of course.

by **Gypsys Kiss** on Sun Jan 04, 2009 4:59 pm

The Neon Peon wrote:
Gypsys Kiss wrote:Are you differentiating between 4, 6 and 8 player doubles, or counting them as the same?

Different, of course.

Just checking

by **Georgerx7di** on Sun Jan 04, 2009 10:12 pm

Nice work neon, looks right to me.

by **TaCktiX** on Sun Jan 04, 2009 11:07 pm

And in the vein of "applications of this" is my crazy tournament Every Single Setting: Classic (see sig). I don't do Freestyle, it's only on Classic, and there is no 2 player, but I did the math and the total number of played games per person would be 450, with the number of games I have to create assuming no mistakes at 1,692.