Attacker's advantage

[The Neon Peon]

How many troops do you generally need to see the effects of attacker's advantage? What is the exact percent?

[Bones2484]

How many troops do you generally need to see the effects of attacker's advantage? What is the exact percent?

4.

[sully800]

The attacker will always have an advantage as long as the attacker rolls 3v2, 3v1 or 2v1.

3v2: 37.2% win, 33.6% tie, 29.3% loss
3v1: 66% win, 34% loss
2v1: 57.9% win, 42.1% loss

As long as there are enough troops to give these "ATTACK INTENSITY LEVELHOOPLAS" the attacker will have an advantage. You can figure out how much by multiplying.

Out of 100 rolls you would expect 37 double wins and 29 double losses. therefore you would come out 16 men ahead in the ideal scenario. In the short run though, you will not always get these results. Expected values only apply to very large numbers.

[The Neon Peon]

The attacker will always have an advantage as long as the attacker roles 3v2, 3v1 or 2v1.

3v2: 37.2% win, 33.6% tie, 29.3% loss
3v1: 66% win, 34% loss
2v1: 57.9% win, 42.1% loss

As long as there are enough troops to give these "ATTACK INTENSITY LEVELHOOPLAS" the attacker will have an advantage. You can figure out how much by multiplying.

Out of 100 rolls you would expect 37 double wins and 29 double losses. therefore you would come out 16 men ahead in the ideal scenario. In the short run though, you will not always get these results. Expected values only apply to very large numbers.

Thanks, just the statistics I was looking for.

[hammocksleeper]

The attacker will always have an advantage as long as the attacker roles 3v2, 3v1 or 2v1.

3v2: 37.2% win, 33.6% tie, 29.3% loss
3v1: 66% win, 34% loss
2v1: 57.9% win, 42.1% loss

Actually it's more like (armies)

3v2: 36% win
3v1: 75% win
2v1: 41% win

In general, if you are attacking 3v1, 4v2, 5v3, 6v4, 7v6 or better, you will have >50% chance of win. And for even matchups, the tipping point occurs at 12v12 where it is now an attacker's advantage - which is why I am always perplexed when a player has a stack of >11 to defend a border when it would be better to just attack the threatening armies (assuming there is only one player threatening that border)

[AceArtemis]

He's talking about rolling 3 dice vs. 2 dice, not attacking a 3 vs. 2.

[GabonX]

The attacker will always have an advantage as long as the attacker roles 3v2, 3v1 or 2v1.

3v2: 37.2% win, 33.6% tie, 29.3% loss
3v1: 66% win, 34% loss
2v1: 57.9% win, 42.1% loss

Actually it's more like (armies)

3v2: 36% win
3v1: 75% win
2v1: 41% win

In general, if you are attacking 3v1, 4v2, 5v3, 6v4, 7v6 or better, you will have >50% chance of win. And for even matchups, the tipping point occurs at 12v12 where it is now an attacker's advantage - which is why I am always perplexed when a player has a stack of >11 to defend a border when it would be better to just attack the threatening armies (assuming there is only one player threatening that border)

3v1 wouldn't result in a 75% win ration for the attacker on account of the possibility of tied dice which go to the defender's advantage.

[hammocksleeper]

The attacker will always have an advantage as long as the attacker roles 3v2, 3v1 or 2v1.

3v2: 37.2% win, 33.6% tie, 29.3% loss
3v1: 66% win, 34% loss
2v1: 57.9% win, 42.1% loss

Actually it's more like (armies)

3v2: 36% win
3v1: 75% win
2v1: 41% win

In general, if you are attacking 3v1, 4v2, 5v3, 6v4, 7v6 or better, you will have >50% chance of win. And for even matchups, the tipping point occurs at 12v12 where it is now an attacker's advantage - which is why I am always perplexed when a player has a stack of >11 to defend a border when it would be better to just attack the threatening armies (assuming there is only one player threatening that border)

3v1 wouldn't result in a 75% win ration for the attacker on account of the possibility of tied dice which go to the defender's advantage.

I am counting tied dice in my figure...if tied dice were thrown out it would be 7/8 chance of winning (87.5%) - for explanation see below - but with tied dice goes to the Defender , the win fraction is smaller, ~75%

assuming tied dice are thrown out and attacker goes until he has only 1 army left:

Since tied dice are thrown out we can reduce this to binary dice. 16 possible unique instances of the first roll (2 dice v 1 die). 8 of these are ties and thrown out. 6 of these result in attacker winning. and 2 of these result in attacker losing one army.

we consider the possible outcomes of battling the remaining armies for these two battles where attacker is 2v1, which for each battle results in two ties (thrown out), one win for A and one win for D. or a fifty percent chance for A & D each, so we take the two battles we started with and assign one each to A & D.

thus we have in total , considering the battles that were not thrown out, we have 7 wins for attacker and 1 for defender, or 87.5% win percentage.