Question for the maths experts

[ahunda]

Ups. Didn´t realise, that this had sparked such an intense debate.

Just to clarify: I was indeed thinking of two separate fronts to take out one player.

For example a player, that has a few territories in North America and a few in Australia (taking the old Classic map as example here). And I can deploy my new armies in a way, that will give me a 50 % chance on each side (chose 50 to make it easy).

And in hindsight the question seems rather dumb and the correct answer (25 %) rather obvious to me.

Cheers.

[theconquerer1995]

Yeah that's easy...
you multiply both strings of possibilities, since it's 2 different fronts and they're not dependent on each other.

So it's (50/100) x (50/100) = (2500/10000) = (25/100) = 25%

Well that's how I remember it... and I'm pretty sure I got that right.

If I dare advise you... don't take 50% shots. That's suicide.

There's the math genius right there

[knubbel]

How do you guys calculate the propability of killing an enemy? Do you have a programm? I always just try to guess, but sometimes I would like to calculate it exact.

http://gamesbyemail.com/Games/Gambit/BattleOdds

Thanks for the link

That is not what I mean. I would like a calculator that tells me the propability of beating more than one country.
For example 10vs5 and the remaining armees vs 3. I know how to calculate it but its a lot of work to do it (especially if there are more than 2 countrys). Does such a program exist or do I have to write it?

[Timminz]

How do you guys calculate the propability of killing an enemy? Do you have a programm? I always just try to guess, but sometimes I would like to calculate it exact.

http://gamesbyemail.com/Games/Gambit/BattleOdds

Thanks for the link

That is not what I mean. I would like a calculator that tells me the propability of beating more than one country.
For example 10vs5 and the remaining armees vs 3. I know how to calculate it but its a lot of work to do it (especially if there are more than 2 countrys). Does such a program exist or do I have to write it?

That link will give you that information. just separate the numbers with a coma. I that case, type "10" in the first box, and "5,3" in the second

[knubbel]

That link will give you that information. just separate the numbers with a coma. I that case, type "10" in the first box, and "5,3" in the second[/quote]

Thanks, very useful!

[RashidJelzin]

Ahem. 25%. Who was right? Ah yeah, me.

[hammocksleeper]

Ups. Didn´t realise, that this had sparked such an intense debate.

Just to clarify: I was indeed thinking of two separate fronts to take out one player.

For example a player, that has a few territories in North America and a few in Australia (taking the old Classic map as example here). And I can deploy my new armies in a way, that will give me a 50 % chance on each side (chose 50 to make it easy).

And in hindsight the question seems rather dumb and the correct answer (25 %) rather obvious to me.

Cheers.

yes, 25%

[Geger]

I have other another question for the math experts :

I have 3 territories to attack 3 different targets. The odds to conquer the targets are same, for example 45%.

What is the odd to conquer :
1. all 3 territories
2. at least 2 territories
3. at least 1 territory

Thanks

[lancehoch]

I have other another question for the math experts :

I have 3 territories to attack 3 different targets. The odds to conquer the targets are same, for example 45%.

What is the odd to conquer :
1. all 3 territories
2. at least 2 territories
3. at least 1 territory

Thanks

All 3: .45^3 = 0.091125 = 9.1125%
2+ of 3: .45^3+3*(.45^2*.55) = .42525 = 42.525%
1+ of 3: .45^3+3*(.45^2*.55)+3*(.45*.55^2) = 0.833625 = 83.3625%

[Aradhus]

I have a question, its not a maths question per se, but it is about maths, and maybe some math experts might know of an answer.

Does anybody know of a math site that teaches you from the basics of high school and upwards? I really want to get back my math skills, and the only way to do that for me would be at the beginning. I found a semi decent site before, but the day after, my laptop died, and when I got a new one I couldn't find the site again.

Can anybody help?

[Geger]

I have other another question for the math experts :

I have 3 territories to attack 3 different targets. The odds to conquer the targets are same, for example 45%.

What is the odd to conquer :
1. all 3 territories
2. at least 2 territories
3. at least 1 territory

Thanks

All 3: .45^3 = 0.091125 = 9.1125%
2+ of 3: .45^3+3*(.45^2*.55) = .42525 = 42.525%
1+ of 3: .45^3+3*(.45^2*.55)+3*(.45*.55^2) = 0.833625 = 83.3625%

Thanks lancehoch

Using http://gamesbyemail.com/Games/Gambit/BattleOdds, if I put 3 troops in 1 territorry and attack 3 nearby territories in follow (all have 3 troops inside), the odds are :
1+ of 3 : 76.9%
2+ of 3 : 29.4%
all 3 : 5.2%

Now... If I put in 3 territories of mine 1 troop each, the odd to conquer their nearby territories with 3 troops inside is 47.02511%. Now I use your formula :
1+ of 3 : .... = 85.1%
2+ of 3 : .... = 45.5%
all 3 : .... = 10.4%

Interesting

Do anybody want to play 1vs1 doodle?