Random 1v1x8 [TPA5] (winner glassyyy)

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Evil Semp
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Re: TPA 5 Random 1v1x8 (1/?)

Post by Evil Semp »

I will play.
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adam666
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Re: TPA 5 Random 1v1x8 (1/?)

Post by adam666 »

in please
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General Bax
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Re: TPA 5 Random 1v1x8 (1/?)

Post by General Bax »

in pls
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Re: TPA 5 Random 1v1x8 (1/?)

Post by JPlo64 »

in please
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Re: TPA 5 Random 1v1x8 (1/?)

Post by Swimmerdude99 »

I'm in!
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rmjw10
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Re: TPA 5 Random 1v1x8 (1/?)

Post by rmjw10 »

in please
morleyjoe
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Re: TPA 5 Random 1v1x8 (1/?)

Post by morleyjoe »

7 of 16 community tournaments run by Atlantis! I like it...count me in
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rmjw10
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Re: TPA 5 Random 1v1x8 (1/?)

Post by rmjw10 »

in please
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Re: TPA 5 Random 1v1x8 (1/?)

Post by iAmCaffeine »

In please mate.
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TAFFATTACK
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Re: TPA 5 Random 1v1x8 (1/?)

Post by TAFFATTACK »

In Please
shoop76
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Re: TPA 5 Random 1v1x8 (1/?)

Post by shoop76 »

rmjw10 wrote:in please


Signing up once is enough, mate.
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Swifte
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Re: TPA 5 Random 1v1x8 (1/?)

Post by Swifte »

shoop76 wrote:All games will be best of 1 until we reach the last 64.

last 64 - best of 3
last 32 - best of 3
last 16 - best of 5
last 8 - best of 5
last 4 - best of 7
Final - best of 9

All brackets, including "finals" will be randomly drawn using challonge.org. It is possible to have multiple entries advancing to the finals bracket and it is possible to be drawn against yourself. If this happens 1 entry automatically advances and the other 1 is eliminated.
No freemiums please as the potential gameload is too high.


Hi shoop - can you give an example of how this works assuming we start with 128 people? Would round 2 of each of the 8 brackets then be best of 3, meaning round 2 could be up to 24 games if you advance in all 8? or is 'last 64' meaning that there are just 64 people left across all 8 brackets?
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ClasslessFool
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Re: TPA 5 Random 1v1x8 (1/?)

Post by ClasslessFool »

sign me up =]
shoop76
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Re: TPA 5 Random 1v1x8 (1/?)

Post by shoop76 »

Swifte wrote:
shoop76 wrote:All games will be best of 1 until we reach the last 64.

last 64 - best of 3
last 32 - best of 3
last 16 - best of 5
last 8 - best of 5
last 4 - best of 7
Final - best of 9

All brackets, including "finals" will be randomly drawn using challonge.org. It is possible to have multiple entries advancing to the finals bracket and it is possible to be drawn against yourself. If this happens 1 entry automatically advances and the other 1 is eliminated.
No freemiums please as the potential gameload is too high.


Hi shoop - can you give an example of how this works assuming we start with 128 people? Would round 2 of each of the 8 brackets then be best of 3, meaning round 2 could be up to 24 games if you advance in all 8? or is 'last 64' meaning that there are just 64 people left across all 8 brackets?


No. Sorry for the confusion. The 8 preliminary brackets will be 1 game throughout. When these 8 brackets reach the last 8 they will qualify for the finals bracket. That is when the games will increase. Don't really want someone to make it to the finals bracket and get eliminated due to a bad drop or bad dice and it being only 1 game.

But the 8 brackets will be only 1 game per round. I hope this explains it.
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Swifte
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Re: TPA 5 Random 1v1x8 (1/?)

Post by Swifte »

Got it now, thank you!

Since I bugged you, I guess I should enter ;)
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Dukasaur
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Re: TPA 5 Random 1v1x8 (1/?)

Post by Dukasaur »

in please
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Re: TPA 5 Random 1v1x8 (1/?)

Post by drake_pk7 »

i would like to join please
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Re: TPA 5 Random 1v1x8 (1/?)

Post by rmjw10 »

count me in
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Re: TPA 5 Random 1v1x8 (1/?)

Post by alster »

In pls.
Gengoldy wrote:Of all the games I've played, and there have been some poor sports and cursing players out there, you are by far the lowest and with the least class.
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dragon dor
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Re: TPA 5 Random 1v1x8 (1/?)

Post by dragon dor »

Dragon here :twisted:
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Re: TPA 5 Random 1v1x8 (1/?)

Post by MattiWacklin »

in please..
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Re: TPA 5 Random 1v1x8 (1/?)

Post by EagleByRob »

sure
wendall2000
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Re: TPA 5 Random 1v1x8 (1/?)

Post by wendall2000 »

In please
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Re: TPA 5 Random 1v1x8 (1/?)

Post by Bobby4254 »

In please.
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