Four Fours Game

[Bones2484]

39 = 44 - (√4 / .4)

We can make two 4s into 44? That kinda makes it silly. Wouldn't that be the Four Forty Fours game?

edit: I guess the first post did it, too. Still think it's silly.

edit2: 40 = 4(4 * √4 + √4)

[theusual1]

If we are allowing 0.4 and 44 to be used, is this ok:

41= 44 - √4 - 4^0

[jonesthecurl]

If we are allowing 0.4 and 44 to be used, is this ok:

41= 44 - √4 - 4^0

No, 'cos it has a digit other than 4 in it.

[jonesthecurl]

Now, if you want a single 4 to be a "1", then somebody tell me what the symbol for "ignore the bit to the right of the decimal point" is (I know there is one, but I forget the conventional way of writing it). Then you could have the square root of the square root of four, ignoring decimals.

[pmchugh]

I would say 44 and 0.4 is ok but not 4^0.

41= ((4! + √4) / .4) - 4!

Odd numers are hard.

[Tupence]

42 = 4! + (4*4) + √4

[pmchugh]

43= 4! + 4! - (√4 / .4)

[theusual1]

I would say 44 and 0.4 is ok but not 4^0.

41= ((4! + √4) / .4) - 4!

Odd numers are hard.

why can we use 0.4 but not 4^0? both use the number 0 so i see no reason why not

[theusual1]

44= √4(4!-4) + 4

[jonesthecurl]

I would say 44 and 0.4 is ok but not 4^0.

41= ((4! + √4) / .4) - 4!

Odd numers are hard.

why can we use 0.4 but not 4^0? both use the number 0 so i see no reason why not

so don't write "0.4". Just write ".4"...

[Tupence]

45 = 44 + 4/4

[Mr. Squirrel]

46 = 44 + (4/√4)

[AceArtemis]

47= 4! + 4! - (4/4)

[gregwolf121]

48=(4+4)*(4+(√4))

[theusual1]

49= 4! + 4! + 4/4

[Megadeth666]

50=44+4+√4

[pmchugh]

51= ((4!-√4)/.4)-4

[Tupence]

52 = 4! + 4! + √4 + √4

[pmchugh]

53=(4!*√4)+(√4/.4)

[theusual1]

54= 4! + 4! + √4 + 4

[qwertylpc]

55=(4^4-((4+√4)^2))/4

I don't know if that counts because im putting a 4 to the 4th power so is that another 4 and also im squaring it and that is represented with a 2 so is that illegal as well??


anyway

55=(4^4-((4+√4)^2))/4
55=(256-((4+2)^2))/4
55=(256-(6^2))/4
55=(256-36)/4
55=220/4
55=55

[sully800]

55=(4^4-((4+√4)^2))/4

I don't know if that counts because im putting a 4 to the 4th power so is that another 4 and also im squaring it and that is represented with a 2 so is that illegal as well??


anyway

55=(4^4-((4+√4)^2))/4
55=(256-((4+2)^2))/4
55=(256-(6^2))/4
55=(256-36)/4
55=220/4
55=55

That definitely does not work, for both reasons you mentioned.

This was a really hard one! I had to use the ceiling notation that jonesthecurl was looking for earlier, and even with that it took some creativity. The ceiling function means round up to the nearest whole number. If the symbol was upside down it would be a floor function and it would mean round down. Too bad I don't know how to type it outside of the equation editor...

[Beckytheblondie]

55= (4!-(4-√4))/.4

The next one is really easy. And if you do a long formula to get it, you'll smack your head when you see how easy it is!

[Beckytheblondie]

Can we use repetends?

[sully800]

55= (4!-(4-√4))/.4

The next one is really easy. And if you do a long formula to get it, you'll smack your head when you see how easy it is!

Nice 55 Becky! Of course I got it in the post above yours, but your solution is good too

As for repetends, the only one you could use would be 0.444... since it can be written as .4... (anything else would require multiple 4's, which is allowed but probably not helpful at this point)

56 = 4! + 4!+ 4 + 4
56 = 24 + 24 + 8
56 = 56

Of course there are tons of ways to get to 56.