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Re: Four Fours Game
Posted: Mon Sep 21, 2009 4:56 pm
by Bones2484
ManBungalow wrote:39 = 44 - (√4 / .4)
We can make two 4s into 44? That kinda makes it silly. Wouldn't that be the Four Forty Fours game?
edit: I guess the first post did it, too. Still think it's silly.
edit2: 40 = 4(4 * √4 + √4)
Re: Four Fours Game
Posted: Tue Sep 22, 2009 7:00 am
by theusual1
If we are allowing 0.4 and 44 to be used, is this ok:
41= 44 - √4 - 4^0
Re: Four Fours Game
Posted: Tue Sep 22, 2009 7:44 am
by jonesthecurl
theusual1 wrote:If we are allowing 0.4 and 44 to be used, is this ok:
41= 44 - √4 - 4^0
No, 'cos it has a digit other than 4 in it.
Re: Four Fours Game
Posted: Tue Sep 22, 2009 7:46 am
by jonesthecurl
Now, if you want a single 4 to be a "1", then somebody tell me what the symbol for "ignore the bit to the right of the decimal point" is (I know there is one, but I forget the conventional way of writing it). Then you could have the square root of the square root of four, ignoring decimals.
Re: Four Fours Game
Posted: Tue Sep 22, 2009 10:08 am
by pmchugh
I would say 44 and 0.4 is ok but not 4^0.
41= ((4! + √4) / .4) - 4!
Odd numers are hard.
Re: Four Fours Game
Posted: Tue Sep 22, 2009 10:11 am
by Tupence
42 = 4! + (4*4) + √4
Re: Four Fours Game
Posted: Tue Sep 22, 2009 10:14 am
by pmchugh
43= 4! + 4! - (√4 / .4)
Re: Four Fours Game
Posted: Tue Sep 22, 2009 11:44 am
by theusual1
pmchugh wrote:I would say 44 and 0.4 is ok but not 4^0.
41= ((4! + √4) / .4) - 4!
Odd numers are hard.
why can we use 0.4 but not 4^0? both use the number 0 so i see no reason why not
Re: Four Fours Game
Posted: Tue Sep 22, 2009 11:47 am
by theusual1
44= √4(4!-4) + 4
Re: Four Fours Game
Posted: Tue Sep 22, 2009 11:48 am
by jonesthecurl
theusual1 wrote:pmchugh wrote:I would say 44 and 0.4 is ok but not 4^0.
41= ((4! + √4) / .4) - 4!
Odd numers are hard.
why can we use 0.4 but not 4^0? both use the number 0 so i see no reason why not
so don't write "0.4". Just write ".4"...
Re: Four Fours Game
Posted: Tue Sep 22, 2009 4:11 pm
by Tupence
45 = 44 + 4/4
Re: Four Fours Game
Posted: Tue Sep 22, 2009 5:20 pm
by Mr. Squirrel
46 = 44 + (4/√4)
Re: Four Fours Game
Posted: Tue Sep 22, 2009 11:29 pm
by AceArtemis
47= 4! + 4! - (4/4)
Re: Four Fours Game
Posted: Wed Sep 23, 2009 2:00 am
by gregwolf121
48=(4+4)*(4+(√4))
Re: Four Fours Game
Posted: Wed Sep 23, 2009 6:47 am
by theusual1
49= 4! + 4! + 4/4
Re: Four Fours Game
Posted: Wed Sep 23, 2009 7:21 am
by Megadeth666
50=44+4+√4
Re: Four Fours Game
Posted: Wed Sep 23, 2009 9:41 am
by pmchugh
51= ((4!-√4)/.4)-4
Re: Four Fours Game
Posted: Wed Sep 23, 2009 9:46 am
by Tupence
52 = 4! + 4! + √4 + √4
Re: Four Fours Game
Posted: Wed Sep 23, 2009 10:00 am
by pmchugh
53=(4!*√4)+(√4/.4)
Re: Four Fours Game
Posted: Thu Sep 24, 2009 6:31 am
by theusual1
54= 4! + 4! + √4 + 4
Re: Four Fours Game
Posted: Mon Oct 12, 2009 1:20 pm
by qwertylpc
55=(4^4-((4+√4)^2))/4
I don't know if that counts because im putting a 4 to the 4th power so is that another 4 and also im squaring it and that is represented with a 2 so is that illegal as well??
anyway
55=(4^4-((4+√4)^2))/4
55=(256-((4+2)^2))/4
55=(256-(6^2))/4
55=(256-36)/4
55=220/4
55=55
Re: Four Fours Game
Posted: Wed Jan 20, 2010 7:33 pm
by sully800
qwertylpc wrote:55=(4^4-((4+√4)^2))/4
I don't know if that counts because im putting a 4 to the 4th power so is that another 4 and also im squaring it and that is represented with a 2 so is that illegal as well??
anyway
55=(4^4-((4+√4)^2))/4
55=(256-((4+2)^2))/4
55=(256-(6^2))/4
55=(256-36)/4
55=220/4
55=55
That definitely does not work, for both reasons you mentioned.
This was a really hard one! I had to use the ceiling notation that jonesthecurl was looking for earlier, and even with that it took some creativity. The ceiling function means round up to the nearest whole number. If the symbol was upside down it would be a floor function and it would mean round down. Too bad I don't know how to type it outside of the equation editor...
Re: Four Fours Game
Posted: Thu Jan 21, 2010 2:27 pm
by Beckytheblondie
55= (4!-(4-√4))/.4
The next one is really easy. And if you do a long formula to get it, you'll smack your head when you see how easy it is!
Re: Four Fours Game
Posted: Thu Jan 21, 2010 2:34 pm
by Beckytheblondie
Can we use repetends?
Re: Four Fours Game
Posted: Thu Jan 21, 2010 6:10 pm
by sully800
Beckytheblondie wrote:55= (4!-(4-√4))/.4
The next one is really easy. And if you do a long formula to get it, you'll smack your head when you see how easy it is!
Nice 55 Becky! Of course I got it in the post above yours, but your solution is good too
As for repetends, the only one you could use would be 0.444... since it can be written as .4... (anything else would require multiple 4's, which is allowed but probably not helpful at this point)
56 = 4! + 4!+ 4 + 4
56 = 24 + 24 + 8
56 = 56
Of course there are tons of ways to get to 56.